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6v^2=726
We move all terms to the left:
6v^2-(726)=0
a = 6; b = 0; c = -726;
Δ = b2-4ac
Δ = 02-4·6·(-726)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{17424}=132$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-132}{2*6}=\frac{-132}{12} =-11 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+132}{2*6}=\frac{132}{12} =11 $
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